Optimal. Leaf size=110 \[ -\frac{a^2 c^2 (A-B) \cos ^5(e+f x)}{5 f (a \sin (e+f x)+a)^5}+\frac{2 B c^2 \cos (e+f x)}{f \left (a^3 \sin (e+f x)+a^3\right )}+\frac{B c^2 x}{a^3}-\frac{2 B c^2 \cos ^3(e+f x)}{3 f (a \sin (e+f x)+a)^3} \]
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Rubi [A] time = 0.264867, antiderivative size = 110, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 4, integrand size = 36, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.111, Rules used = {2967, 2859, 2680, 8} \[ -\frac{a^2 c^2 (A-B) \cos ^5(e+f x)}{5 f (a \sin (e+f x)+a)^5}+\frac{2 B c^2 \cos (e+f x)}{f \left (a^3 \sin (e+f x)+a^3\right )}+\frac{B c^2 x}{a^3}-\frac{2 B c^2 \cos ^3(e+f x)}{3 f (a \sin (e+f x)+a)^3} \]
Antiderivative was successfully verified.
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Rule 2967
Rule 2859
Rule 2680
Rule 8
Rubi steps
\begin{align*} \int \frac{(A+B \sin (e+f x)) (c-c \sin (e+f x))^2}{(a+a \sin (e+f x))^3} \, dx &=\left (a^2 c^2\right ) \int \frac{\cos ^4(e+f x) (A+B \sin (e+f x))}{(a+a \sin (e+f x))^5} \, dx\\ &=-\frac{a^2 (A-B) c^2 \cos ^5(e+f x)}{5 f (a+a \sin (e+f x))^5}+\left (a B c^2\right ) \int \frac{\cos ^4(e+f x)}{(a+a \sin (e+f x))^4} \, dx\\ &=-\frac{a^2 (A-B) c^2 \cos ^5(e+f x)}{5 f (a+a \sin (e+f x))^5}-\frac{2 B c^2 \cos ^3(e+f x)}{3 f (a+a \sin (e+f x))^3}-\frac{\left (B c^2\right ) \int \frac{\cos ^2(e+f x)}{(a+a \sin (e+f x))^2} \, dx}{a}\\ &=-\frac{a^2 (A-B) c^2 \cos ^5(e+f x)}{5 f (a+a \sin (e+f x))^5}-\frac{2 B c^2 \cos ^3(e+f x)}{3 f (a+a \sin (e+f x))^3}+\frac{2 B c^2 \cos (e+f x)}{f \left (a^3+a^3 \sin (e+f x)\right )}+\frac{\left (B c^2\right ) \int 1 \, dx}{a^3}\\ &=\frac{B c^2 x}{a^3}-\frac{a^2 (A-B) c^2 \cos ^5(e+f x)}{5 f (a+a \sin (e+f x))^5}-\frac{2 B c^2 \cos ^3(e+f x)}{3 f (a+a \sin (e+f x))^3}+\frac{2 B c^2 \cos (e+f x)}{f \left (a^3+a^3 \sin (e+f x)\right )}\\ \end{align*}
Mathematica [B] time = 0.684357, size = 272, normalized size = 2.47 \[ \frac{(c-c \sin (e+f x))^2 \left (\sin \left (\frac{1}{2} (e+f x)\right )+\cos \left (\frac{1}{2} (e+f x)\right )\right ) \left (24 (A-B) \sin \left (\frac{1}{2} (e+f x)\right )+2 (3 A-43 B) \sin \left (\frac{1}{2} (e+f x)\right ) \left (\sin \left (\frac{1}{2} (e+f x)\right )+\cos \left (\frac{1}{2} (e+f x)\right )\right )^4+4 (3 A-8 B) \left (\sin \left (\frac{1}{2} (e+f x)\right )+\cos \left (\frac{1}{2} (e+f x)\right )\right )^3-8 (3 A-8 B) \sin \left (\frac{1}{2} (e+f x)\right ) \left (\sin \left (\frac{1}{2} (e+f x)\right )+\cos \left (\frac{1}{2} (e+f x)\right )\right )^2-12 (A-B) \left (\sin \left (\frac{1}{2} (e+f x)\right )+\cos \left (\frac{1}{2} (e+f x)\right )\right )+15 B (e+f x) \left (\sin \left (\frac{1}{2} (e+f x)\right )+\cos \left (\frac{1}{2} (e+f x)\right )\right )^5\right )}{15 a^3 f (\sin (e+f x)+1)^3 \left (\cos \left (\frac{1}{2} (e+f x)\right )-\sin \left (\frac{1}{2} (e+f x)\right )\right )^4} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.123, size = 249, normalized size = 2.3 \begin{align*} 2\,{\frac{B{c}^{2}\arctan \left ( \tan \left ( 1/2\,fx+e/2 \right ) \right ) }{f{a}^{3}}}+16\,{\frac{A{c}^{2}}{f{a}^{3} \left ( \tan \left ( 1/2\,fx+e/2 \right ) +1 \right ) ^{4}}}-16\,{\frac{B{c}^{2}}{f{a}^{3} \left ( \tan \left ( 1/2\,fx+e/2 \right ) +1 \right ) ^{4}}}-2\,{\frac{A{c}^{2}}{f{a}^{3} \left ( \tan \left ( 1/2\,fx+e/2 \right ) +1 \right ) }}+2\,{\frac{B{c}^{2}}{f{a}^{3} \left ( \tan \left ( 1/2\,fx+e/2 \right ) +1 \right ) }}-{\frac{32\,A{c}^{2}}{5\,f{a}^{3}} \left ( \tan \left ({\frac{fx}{2}}+{\frac{e}{2}} \right ) +1 \right ) ^{-5}}+{\frac{32\,B{c}^{2}}{5\,f{a}^{3}} \left ( \tan \left ({\frac{fx}{2}}+{\frac{e}{2}} \right ) +1 \right ) ^{-5}}-16\,{\frac{A{c}^{2}}{f{a}^{3} \left ( \tan \left ( 1/2\,fx+e/2 \right ) +1 \right ) ^{3}}}+{\frac{32\,B{c}^{2}}{3\,f{a}^{3}} \left ( \tan \left ({\frac{fx}{2}}+{\frac{e}{2}} \right ) +1 \right ) ^{-3}}+8\,{\frac{A{c}^{2}}{f{a}^{3} \left ( \tan \left ( 1/2\,fx+e/2 \right ) +1 \right ) ^{2}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 1.57486, size = 1531, normalized size = 13.92 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 1.74236, size = 656, normalized size = 5.96 \begin{align*} -\frac{60 \, B c^{2} f x -{\left (15 \, B c^{2} f x -{\left (3 \, A - 43 \, B\right )} c^{2}\right )} \cos \left (f x + e\right )^{3} - 12 \,{\left (A - B\right )} c^{2} -{\left (45 \, B c^{2} f x -{\left (9 \, A + 11 \, B\right )} c^{2}\right )} \cos \left (f x + e\right )^{2} + 6 \,{\left (5 \, B c^{2} f x -{\left (A - 11 \, B\right )} c^{2}\right )} \cos \left (f x + e\right ) +{\left (60 \, B c^{2} f x + 12 \,{\left (A - B\right )} c^{2} -{\left (15 \, B c^{2} f x +{\left (3 \, A - 43 \, B\right )} c^{2}\right )} \cos \left (f x + e\right )^{2} + 6 \,{\left (5 \, B c^{2} f x +{\left (A + 9 \, B\right )} c^{2}\right )} \cos \left (f x + e\right )\right )} \sin \left (f x + e\right )}{15 \,{\left (a^{3} f \cos \left (f x + e\right )^{3} + 3 \, a^{3} f \cos \left (f x + e\right )^{2} - 2 \, a^{3} f \cos \left (f x + e\right ) - 4 \, a^{3} f +{\left (a^{3} f \cos \left (f x + e\right )^{2} - 2 \, a^{3} f \cos \left (f x + e\right ) - 4 \, a^{3} f\right )} \sin \left (f x + e\right )\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.21275, size = 215, normalized size = 1.95 \begin{align*} \frac{\frac{15 \,{\left (f x + e\right )} B c^{2}}{a^{3}} - \frac{2 \,{\left (15 \, A c^{2} \tan \left (\frac{1}{2} \, f x + \frac{1}{2} \, e\right )^{4} - 15 \, B c^{2} \tan \left (\frac{1}{2} \, f x + \frac{1}{2} \, e\right )^{4} - 60 \, B c^{2} \tan \left (\frac{1}{2} \, f x + \frac{1}{2} \, e\right )^{3} + 30 \, A c^{2} \tan \left (\frac{1}{2} \, f x + \frac{1}{2} \, e\right )^{2} - 170 \, B c^{2} \tan \left (\frac{1}{2} \, f x + \frac{1}{2} \, e\right )^{2} - 100 \, B c^{2} \tan \left (\frac{1}{2} \, f x + \frac{1}{2} \, e\right ) + 3 \, A c^{2} - 23 \, B c^{2}\right )}}{a^{3}{\left (\tan \left (\frac{1}{2} \, f x + \frac{1}{2} \, e\right ) + 1\right )}^{5}}}{15 \, f} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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